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2a^2-137a+340=0
a = 2; b = -137; c = +340;
Δ = b2-4ac
Δ = -1372-4·2·340
Δ = 16049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-137)-\sqrt{16049}}{2*2}=\frac{137-\sqrt{16049}}{4} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-137)+\sqrt{16049}}{2*2}=\frac{137+\sqrt{16049}}{4} $
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